Wireshark · Wireshark-users: Re: [Wireshark-users] Average MBit/sec

["ronnie sahlberg" <ronniesahlberg@xxxxxxxxx>]

unless you use >=1GbE or FC physical layers where there are 10 bits
per byte in the physical transport.

(but we never see the real physical layer in wireshark anyway)

On Wed, Feb 27, 2008 at 12:54 PM, Stephen Fisher
<stephentfisher@xxxxxxxxx> wrote:
> On Tue, Feb 26, 2008 at 05:45:12PM -0800, Greg Reed wrote:
>
>  > For MB/sec would I move the decimal point 2 places to the right from
>  > the output of MBit/sec?
>
>  There are 8 bits in a byte, so you would actually multiply the MBit/sec
>  by 8 to get MB[yte]/sec.
>
>
>  Steve
>
>
>
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