Wireshark-users: Re: [Wireshark-users] Average MBit/sec
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From: Jehanzeb Khan <jehanzeb.khan@xxxxxxxxx>
Date: Tue, 26 Feb 2008 21:59:10 -0800 (PST)
Stephen i think you meant to say 'divide' by 8 to go from MBit/Sec to MB[yte]/sec :)
 
Regards
Jehanzeb Khan

Stephen Fisher <stephentfisher@xxxxxxxxx> wrote:
On Tue, Feb 26, 2008 at 05:45:12PM -0800, Greg Reed wrote:

> For MB/sec would I move the decimal point 2 places to the right from
> the output of MBit/sec?

There are 8 bits in a byte, so you would actually multiply the MBit/sec
by 8 to get MB[yte]/sec.


Steve

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