which stands for 3 in ascii table,
0x33 [hex]= 51[decimal] = 3 [char]
so the version should be right. ;)
-----Ursprüngliche Nachricht-----
Datum: Fri, 27 Jun 2008 13:56h
Von: "Luis EG Ontanon" <luis@xxxxxxxxxxx>
An: "Community support list for Wireshark" <wireshark-users@xxxxxxxxxxxxx>
Betreff: Re: [Wireshark-users] TPKT-Wrapping of H.248 Messages
The problem is that Wireshark won't decode TPKT where version != 3. In
your case the verion is 0x33.
Is that right or that's a fault on the MG's TPKT implementation?
\\Lego
On Fri, Jun 27, 2008 at 12:17 PM, Umut Emin <j.s.bach@xxxxxxxxxxx> wrote:
> Hello,
>
> i have the following question:
>
> if i send a h.248 message (over TCP) wrapped with tpkt header, wireshark doesn't recognize
> the h.248 transfer. It shows me a package of TPKT protocol with info "Continuation"
> which is fine. As i want to see what is in the package it doesn't form an expected
> structure like:
> TPKT: version:3 length:1024
> MEGACO:.
> ..
> ....
>
> It shows the h.248 message as a raw "Data".
>
> Now my application creates a TPKT header as explained in RFC 1006 which means:
>
> version no = 3 (1 byte)
> reserved = 0x01 (1 byte)
> message length = 1024 (2 bytes) [including the tpkt header]
>
> and these values are added as 4 bytes in the beginning of the send buffer. Now i wonder
> if wireshark is not able to work with tpkt on h.248 yet?
>
> For clarity, i included a dump from the wire (see package no:4) as attachment.
>
> Thanx in advance.
> Umut
>
>
>
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>
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