Wireshark-dev: Re: [Wireshark-dev] Slot on main thread not called when signal is emitted from a
From: Paul Offord <Paul.Offord@xxxxxxxxxxxx>
Date: Wed, 16 Dec 2015 14:45:42 +0000
Well that was frustrating. The answer to my problem is that I had mixed release and debug objects. I have been adding Qt Libraries to the Linker Input list like this: \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Core.lib \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Widgets.lib \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Gui.lib \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Network.lib I have now changed the include list to: \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Cored.lib \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Widgetsd.lib \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Guid.lib \Qt\Qt5.5.1\5.5\msvc2013_64\lib\Qt5Networkd.lib Now QApplication::instance() returns the pointer and my slot is now working. Thanks Gerald for your advice, which in a roundabout way led me to the solution. Best regards...Paul -----Original Message----- From: Paul Offord Sent: 16 December 2015 11:45 To: Developer support list for Wireshark <wireshark-dev@xxxxxxxxxxxxx> Subject: RE: [Wireshark-dev] Slot on main thread not called when signal is emitted from another thread Sorry - ignore that stupid last question about class name vs. instance. I should have researched the function a little so I understood what you are driving at. I did a bit of research and it seems that although QApplication::instance() doesn't exist but QCoreApplication::instance() does. I've tried it as a direct replacement and that doesn't work but I've seen a lot of chit chat on the Qt forum about recasting the returned pointer so I'll look further. Best regards...Paul -----Original Message----- From: wireshark-dev-bounces@xxxxxxxxxxxxx [mailto:wireshark-dev-bounces@xxxxxxxxxxxxx] On Behalf Of Paul Offord Sent: 16 December 2015 11:30 To: Developer support list for Wireshark <wireshark-dev@xxxxxxxxxxxxx> Subject: Re: [Wireshark-dev] Slot on main thread not called when signal is emitted from another thread Do you mean like this? syncro.h #ifndef SYNCRO_H #define SYNCRO_H #include <QtCore> #include "mythread.h" class Syncro : public QObject { Q_OBJECT public: Syncro(); void Initialise(MyThread *); public slots: void jumpToFrame(int); }; #endif // SYNCRO_H Syncro.cpp . . Syncro::Syncro() { setParent(QApplication::instance()); } . . The setParent(QApplication::instance()) shows as an error in VS - incomplete type is not allowed. Don't I have to specify the QApplication instance rather than the class name? Cheers...Paul -----Original Message----- From: wireshark-dev-bounces@xxxxxxxxxxxxx [mailto:wireshark-dev-bounces@xxxxxxxxxxxxx] On Behalf Of Gerald Combs Sent: 15 December 2015 21:19 To: Developer support list for Wireshark <wireshark-dev@xxxxxxxxxxxxx> Subject: Re: [Wireshark-dev] Slot on main thread not called when signal is emitted from another thread On 12/15/15 8:15 AM, Paul Offord wrote: > When I run the code the extra thread starts OK and it starts to cycle > around the loop with the 3 second sleep. However, the connected slot > function Syncro::jumpToFrame(int new_frame) does not get called. If I > change the connect from QueuedConnection to DirectConnection the slot > function gets called but, as expected, in the context of my serviceThread. > I need the slot function to run on the main thread. > > I guess it is because my jumpToFrame slot function is not on the main > thread event loop, but I don’t understand how to get it on the loop. Can you try adding a constructor to Syncro, and add either moveToThread(QApplication::instance()->thread()); or setParent(QApplication::instance()); to it? I'm not sure if QObjects have a valid thread affinity by default. ___________________________________________________________________________ Sent via: Wireshark-dev mailing list <wireshark-dev@xxxxxxxxxxxxx> Archives: https://www.wireshark.org/lists/wireshark-dev Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev mailto:wireshark-dev-request@xxxxxxxxxxxxx?subject=unsubscribe ______________________________________________________________________ This message contains confidential information and is intended only for the individual named. If you are not the named addressee you should not disseminate, distribute or copy this e-mail. Please notify the sender immediately by e-mail if you have received this e-mail by mistake and delete this e-mail from your system. 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