Ethereal-dev: Re: [Ethereal-dev] PPP dissector bug

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From: Irfan Khan <ikhan@xxxxxxxxxxxx>
Date: Mon, 10 Mar 2003 20:33:26 -0700


On Mon, Mar 10, 2003 at 08:15:22PM -0700, Irfan Khan wrote:

0x7e is escaped in PPP (preceded by 0x7d).


To be precise, 0x7e is escaped in PPP in HDLC-like framing.  However, at
least as I read the L2TP spec, the framing is supposed to be removed by
the time the packets are encapsulated in L2TP, so that a 0x7e is just a
0x7e.
Yes a 0x7e becomes a 0x7e 0x5e. I see what you are saying a protocol with a protocol number 0x7e 0xkk would not work in this case.